Isn’t the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn’t it be more correct to make it equal to ++i
They’re especially also a source of bugs, because they encourage manually incrementing indices and manually accessing array positions, which is almost never actually sensible.
In C you can group expressions within ( and ) separated with ,. Expressions are evaluated in order and the last expression in the group is the returned value of the group.
Isn’t the evaluated value different from the expression?
i++returns the value of i before increasing.i-=-1would return the value after it has been increased. Wouldn’t it be more correct to make it equal to++iIn the languages I know,
i-=-1orx=3are not expressions, but rather statements, so they do not evaluate to a value.So, this would be a compiler error:
a = (x=3)Well, not all languages allow for fun programming :)
Sounds like the opposite of fun to me, to have those as expressions…
And that’s why post- and pre-increment is non-existant in Python and Rust. It’s an easy source for bugs for a noncritical abbreviation🤷
They’re especially also a source of bugs, because they encourage manually incrementing indices and manually accessing array positions, which is almost never actually sensible.
Please explain in less detail to help me understand, internet friend.
In C you can group expressions within
(and)separated with,. Expressions are evaluated in order and the last expression in the group is the returned value of the group.