orhtej2@eviltoast.org to Programmer Humor@programming.devEnglish · 1 year agoPeak code reuseeviltoast.orgimagemessage-square41linkfedilinkarrow-up1471arrow-down16
arrow-up1465arrow-down1imagePeak code reuseeviltoast.orgorhtej2@eviltoast.org to Programmer Humor@programming.devEnglish · 1 year agomessage-square41linkfedilink
minus-squarecogman@lemmy.worldlinkfedilinkarrow-up7·1 year agoFixed boolean isOdd(int num) { if(num == 1) return true; if(num > 0) return isEven(num - 1); else return isEven(num + 1); } boolean isEven(int num) { if(num > 0) return isOdd(num - 1); else return isOdd(num + 1); }
minus-squareaffiliate@lemmy.worldlinkfedilinkarrow-up11·1 year agothe downside with this approach is that it will eventually terminate. the version in the original post has the advantage of giving me plenty of time to contemplate life’s many mysteries.
minus-squarecogman@lemmy.worldlinkfedilinkarrow-up4·1 year agoWhat can I say, I’m a performance nerd.
minus-squareRednax@lemmy.worldlinkfedilinkarrow-up3arrow-down2·1 year agoWhy the complicated if statements to check the sign? Just let the number overflow. Would be functionaly the same, and result in much prettier code.
minus-squarecogman@lemmy.worldlinkfedilinkarrow-up6·1 year agoThat’s a platform dependent change. Overflow is undefined behavior. I’d rather have my code portable so it can run on my Univac 1101.
Fixed
the downside with this approach is that it will eventually terminate. the version in the original post has the advantage of giving me plenty of time to contemplate life’s many mysteries.
What can I say, I’m a performance nerd.
Why the complicated if statements to check the sign? Just let the number overflow. Would be functionaly the same, and result in much prettier code.
That’s a platform dependent change. Overflow is undefined behavior. I’d rather have my code portable so it can run on my Univac 1101.
isEeven(∞);